In the rectangle method, the function to integrate \( f \) is replaced by a piecewise constant function \( g(x) \) on each elementary interval \([x_{i-1}, x_i]\):

  • Left rectangles: \( g(x) = f(x_{i-1}) \) for \( x \in [x_{i-1}, x_i] \)
  • Right rectangles: \( g(x) = f(x_i) \) for \( x \in [x_{i-1}, x_i] \)
  • Midpoint rectangles: \( g(x) = f\left(\frac{x_{i-1}+x_i}{2}\right) \) for \( x \in [x_{i-1}, x_i] \)

The associated integration formulas are:

Left rectangles: ∫ab f(x) dx ≈ Σi=1n (x_i - x_{i-1}) f(x_{i-1})
Right rectangles: ∫ab f(x) dx ≈ Σi=1n (x_i - x_{i-1}) f(x_i)
Midpoint rectangles: ∫ab f(x) dx ≈ Σi=1n (x_i - x_{i-1}) f((x_{i-1}+x_i)/2)

If the subdivision is uniform with step \( h = \frac{b-a}{n} \), then:

Left rectangles: ∫ab f(x) dx ≈ h Σi=0n-1 f(x_i)
Right rectangles: ∫ab f(x) dx ≈ h Σi=1n f(x_i)
Midpoint rectangles: ∫ab f(x) dx ≈ h Σi=1n f((x_{i-1}+x_i)/2)

Error

The left and right rectangle methods are order 0. If the first derivative of \( f \) is bounded by \( M \):

Left rectangles: | ∫ab f(x) dx - h Σi=0n-1 f(x_i) | ≤ (b-a)/2 × h × sup |f'(x)|
Right rectangles: | ∫ab f(x) dx - h Σi=1n f(x_i) | ≤ (b-a)/2 × h × sup |f'(x)|

The midpoint rectangle method is order 1. If \( f \in C^2([a,b]) \):

| ∫ab f(x) dx - h Σi=1n f((x_{i-1}+x_i)/2) | ≤ (b-a)/24 × h² × sup |f''(x)|

Numerical Example

Evaluate numerically ∫02 sin(x) dx with n=3 (h=2/3):

i x_i f(x_i) = sin(x_i)
0 0 0
1 2/3 ≈ 0.6184
2 4/3 ≈ 0.9705
3 2 ≈ 0.9093

Midpoints:

i (x_{i-1}+x_i)/2 f(midpoint)
1 1/3 ≈ 0.3270
2 1 ≈ 0.8415
3 5/3 ≈ 0.9950

Results:

  • Left rectangles: Rg = (2/3)(0 + 0.6184 + 0.9705) ≈ 1.0586
  • Right rectangles: Rd = (2/3)(0.6184 + 0.9705 + 0.9093) ≈ 1.6646
  • Midpoint rectangles: Rm = (2/3)(0.3270 + 0.8415 + 0.9950) ≈ 1.5410

The exact integral is I(f) = 1 − cos(2) ≈ 1.4161. Relative errors are:

  • Error(Rg) = |1.4161 − 1.0586| ≈ 0.3575 → 25.23%
  • Error(Rd) = |1.6646 − 1.4161| ≈ 0.2485 → 17.55%
  • Error(Rm) = |1.5410 − 1.4161| ≈ 0.1249 → 8.82%
Modifié le: samedi 15 novembre 2025, 02:57